3y+2y^2=20

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Solution for 3y+2y^2=20 equation:


Simplifying
3y + 2y2 = 20

Solving
3y + 2y2 = 20

Solving for variable 'y'.

Reorder the terms:
-20 + 3y + 2y2 = 20 + -20

Combine like terms: 20 + -20 = 0
-20 + 3y + 2y2 = 0

Factor a trinomial.
(-4 + -1y)(5 + -2y) = 0

Subproblem 1

Set the factor '(-4 + -1y)' equal to zero and attempt to solve: Simplifying -4 + -1y = 0 Solving -4 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1y = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1y = 0 + 4 -1y = 0 + 4 Combine like terms: 0 + 4 = 4 -1y = 4 Divide each side by '-1'. y = -4 Simplifying y = -4

Subproblem 2

Set the factor '(5 + -2y)' equal to zero and attempt to solve: Simplifying 5 + -2y = 0 Solving 5 + -2y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -2y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -2y = 0 + -5 -2y = 0 + -5 Combine like terms: 0 + -5 = -5 -2y = -5 Divide each side by '-2'. y = 2.5 Simplifying y = 2.5

Solution

y = {-4, 2.5}

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